def divide(a, b):
    try:
        return a / b
    except:
        x = 17

My smart exception handling before meeting "pass" :))

By mophix, 2017-12-15 18:13:07
zipped_file.extractall(f'{file_path}')
zipped_file.close()
By Anonymous, 2017-12-19 10:29:52
{k: v for d in [{ key: { 0: x[0], } for key in x["name"] } for x in items] for k, v in d.items()}
By nooooooo, 2018-01-02 14:54:31
for x,x1 in enumerate(hack):
 
        if hack[x] in letters:
            exception +=1

ffs why

By just why, 2018-02-05 01:25:30
if student_id:
    assignments = Assignment.objects.filter(week__in=weeks)

    unenrolled_students = Wave.objects.filter(week__in=weeks).values_list('unenrolled_students', flat=True)

    # Construct responses based on assignment type
    Assignment.build_assignments_for_weeks(responses, assignments, students, unenrolled_students)
    max_num_assessments = Assessment.build_assessments_for_weeks(responses)
    Comment.build_comments_for_weeks(responses, weeks, students, unenrolled_students)

elif wave_id:
    assignments = Assignment.objects.filter(week__in=weeks)

    unenrolled_students = Wave.objects.filter(week__in=weeks).values_list('unenrolled_students', flat=True)

    # Construct responses based on assignment type
    Assignment.build_assignments_for_weeks(responses, assignments, students, unenrolled_students)
    max_num_assessments = Assessment.build_assessments_for_weeks(responses)
    Comment.build_comments_for_weeks(responses, weeks, students, unenrolled_students)

else:
    # can't happen
    pass
By Anonymous, 2018-03-23 12:46:10
def possibilities():
    alphabets=(n,o,r,t,h,e,a,s,u,w,m,y)
    combinations=list()
    for n in range(9,-1,-1):
            for o in range(9,-1,-1):
                    for r in range(9,-1,-1):
                            for t in range(9,-1,-1):
                                    for h in range(9,-1,-1):
                                            for e in range(9,-1,-1):
                                                    for a in range(9,-1,-1):
                                                            for s in range(9,-1,-1):
                                                                    for u in range(9,-1,-1):
                                                                            for w in range(9,-1,-1):
                                                                                    for m in range(9,-1,-1):
                                                                                            for y in range(9,-1,-1):
                                                                                                    if len(set([n,o,r,t,h,e,a,s,u,w,m,y]))==12:
                                                                                                    north=10000*n + 1000*o +100*r +10*t +h
                                                                                                    east=1000*e +100*a +10*s +t
                                                                                                    south=10000*s + 1000*o +100*u +10*t +h
                                                                                                    west=1000*w + 100*e +10*s +t
                                                                                                    earth= 10000*e + 1000*a + 100*r +10*t +h
                                                                                                    if north +east +south +west == earth:
                                                                                                            combinations.append((north,east,south,west,earth))

    return combinations
By Dusk Code, 2018-04-25 11:47:49

    def dow_to_dict_from_self(self):
        # res = {'name': self.name, 'enabled': self.enabled }
        res = {'sun': 0, 'mon': 0, 'tue': 0, 'wed': 0, 'thr': 0, 'fri': 0,
               'sat': 0,
               'enabled': 0, 'dow': 0, 'name': 'untitled'}

        if (int(self.days_of_week) & 0x01) == 0x01:  # sun
            res['sun'] = 1
        if (int(self.days_of_week) & 0x02) == 0x02:  # mon
            res['mon'] = 1
        if (int(self.days_of_week) & 0x04) == 0x04:  # tue
            res['tue'] = 1
        if (int(self.days_of_week) & 0x08) == 0x08:  # wed
            res['wed'] = 1
        if (int(self.days_of_week) & 0x10) == 0x10:  # thr
            res['thr'] = 1
            res['thu'] = 1  # '%a' returns thu for Thursday
        if (int(self.days_of_week) & 0x20) == 0x20:  # fri
            res['fri'] = 1
        if (int(self.days_of_week) & 0x40) == 0x40:  # sat
            res['sat'] = 1
        if (int(
                self.days_of_week) & 0x40) == 0x80:  # enabled # new enable#
            # flag -- duplicate in db
            res['enabled'] = 1

        res['enabled'] = self.enabled  # remove this
        res['dow'] = self.days_of_week
        res['name'] = self.name

        return res

kept the original comments - they're very helpful

By Anonymous, 2018-07-11 19:40:44
# Weird list cleanup
product = "{0}".format(list(product))
product = re.sub(r"\), \(+", "], [", product)
product = re.sub(r"\(+", "[", product)
product = product.replace(")]", "]]").replace(")", "")
product = ast.literal_eval(product)

I don't know why I get this strange fomat for this array of objects... Ok let's do it fast: 1 - Convert array in string 2 - Clean up string 3 - Convert string in array

By Anonymous, 2018-09-05 23:51:16
product = None
for key in dictionary.keys():
	if product is None:
		product = dictionary[key]
	else:
		product = itertools.product(product, dictionary[key])

product = "{0}".format(list(product))
product = re.sub(r"\), \(+", "], [", product)
product = re.sub(r"\(+", "[", product)
product = product.replace(")]", "]]").replace(")", "")
product = ast.literal_eval(product)

Ok, I have a weird array of objects as output of itertools and I need an array of strings... 1 - Convert the array to string 2 - Clean it up with regex and replace 3 - Convert the string to array 4 - Problem solved

By AnonimaPitoni, 2018-09-06 00:27:34
def __getCurlOutput (self, url, **kwargs):
	curlcmd = "curl {0}".format(url)

	for key, value in kwargs.items():
		key = key.lower()

		if key == "origin":
			curlcmd += " -H 'Origin: {0}'".format(value)
		elif key == "contenttype":
			curlcmd += " -H 'Content-Type: {0}'".format(value)
		elif key == "referer":
			curlcmd += " -H 'Referer: {0}'".format(value)
		elif key == "cookie":
			curlcmd += " -H 'Cookie: {0}'".format(value)
		elif key == "data":
			curlcmd += " --data '{0}'".format(value)
		elif key == "verbose":
			if value == True:
				curlcmd += " --verbose"
			else:
				curlcmd += " --silent"
		elif key == "output":
			curlcmd += " --output {0}".format(value)
		else:
			print "Unsupported key: {0}".format(key)

	curlcmd += " 2>&1"

	print curlcmd

	curlout = subprocess.check_output(curlcmd,shell=True)

	return curlout
By AnonimaPitoni, 2018-12-04 19:22:34
for data1, data2 in zip(results, results[1:]):
    assert data1 <= data1
    if data1 == data1:
        assert data1 >= data1

A nice loop for making sure that data1 is equal to data1!

By 1133, 2018-12-10 14:43:50
return [word for word in words if any(all(ch in row for ch in word.lower()) for row in rows)]

Filtering words that can be typed using only one row of the keyboard.

By Mark, 2019-02-27 15:53:46
try:
    raise
except RuntimeError:
    raise

try this in python3

By FranchuFranchu, 2019-03-14 23:10:03
def get_schema(self, schema: object) -> object:
    """Get the Schema class
    """
    if isinstance(schema, str):
        Schema = getattr(self.request["operation"], schema, None)
    else:
        Schema = schema
    if Schema is None:
        Schema = getattr(self, schema, None)
        if Schema is None:
            raise web.HTTPNotImplemented
    return Schema

I don't even know what to say

By why, 2019-05-23 20:19:52
# Create vpc peering connection
response = ec2.delete_vpc_peering_connection(peer_connection_id)

a part of AWS Landing Zone solution

By Amazon Solutions, 2019-07-10 12:49:42